>
>
>
> --- In oopic@yahoogroups.com, "m_elias" <m_elias@> wrote:
> >
> > Any further progress on this? I too am having difficulty
understanding
> > how the "Banks" (0-3) are arranged. The compiler (v6) denotes the
> > "area" (A,I,V) and the address but I can't figure out how to
> > successfully address anything other than in "Object Default
Property"
> > mode.
> >
>
>
>
> m_elias,
>
> Certainly!
>
> The statement in my previous post turns out to work for me. I'm
> currently using it without problems.
>
> "This test would imply that things in Area A, and Area I need a sub
> address bank of 0, whereas things in Area V need a sub address bank of
> 2. I have no idea what Area F is for."
>
> Hope it works for you.
>
> Dogulas
>
Thanks Doug,
I did some testing using a similar technique to what 'jeffmaya'
suggested in another post,
For i = 0 to 127
MSComm1.Output = i & "J"
MSComm1.Output = "144H"
MSComm1.Output = "M"
DoEvents
Next 'i
I used that to determine which Banks contained what. You are correct,
V area = Variable Memory = Bank 2
A Area = Object Memory = Bank 0
I Area = end of Object Memory(oByte type stuff) = Bank 0
[Non-text portions of this message have been removed]
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