inputs. The input1 and input2 are data inputs (note that there is no
input) and you would need to use oBus to link that to something.
DLC
Shaggy wrote:
> In putting together some odometer code, I wanted to move the value from the
> oQuadencode count to a oWord object all in a virtual circuit. To move a
> word, I figured that the way to go would be the oMath object in cvLatch
> mode. However, I wanted to do that once every second, so I used the oMathC
> object and tried to link the ooPIC.Hz1 to the timer. I used several
> variations of this line:
>
> (assuming that lMath is declared as New oMathC)
>
> lMath.Process.Input.Link(ooPIC.Hz1)
>
> I get an error saying that Input is not a member of oMath. I note that the
> compiler is not saying that it is not an error of oMathC. To test this, I
> changed oMathC to oMathO, and got other errors that specifically referred to
> the oMathO object. Since the error I am getting refers to the oMath object,
> rather than the oMathC object, it leads me to believe that the oMathC is not
> actually implemented, despite using B2.2+ (which appears to include the
> oMathC object).
>
> Any suggestions?
--
------------------------------------------------------
Dennis Clark ooPIC Tech Support
www.oopic.com
------------------------------------------------------
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