[oopic] Re: Help with OO code

Thanks Richard, but the *X objects don't work either. It has more to
do with the default property of the object I think because linking it
to what I thought was obvious kicks up an error that reads "Expecting
an oLogic Object or an object with the default property of oLogic"
but I don't have enough experience to pick the right one (?) or I
don't understand it well enought yet.

--- In oopic@yahoogroups.com, "rtstofer" <rstofer@...> wrote:
>
> --- In oopic@yahoogroups.com, "Mike Martin" <xaviour2me@> wrote:
> >
> > Would anyone be kind enough to tell me where I'm going wrong here
> > please? I'm trying to write OO code to link a potentiometer to a
> > servo to make it change its position. I can do it with procedural
> > code OK but don't know what object to use in order to make it
work
> > with OO. Info about linking is a little thin - I need a link to a
> > really good explaination to read about objects, pointers and
flags if
> > any has one?
> > TIA
> > Mike M.
> >
> > 'Positions a servo using the .position of an
> > 'oKnob Object (trim pot)
> > Dim Srv As New oServo 'Make a servo object.
> > Dim Pot As New oKnob 'Make a knob object
> > Dim Wire As New oWire
> >
> > Sub main()
> > ooPIC.Node = 1
> > Call Setup
> > End Sub
> >
> > Sub Setup() 'Setup servo properties
> > Srv.IOLine = 31 'set the servo to use I/O Line 31
> > Srv.Adjust = 28 'set the servos center to 28
> > Srv.Operate =cvTrue 'turn the Servo on
> > Pot.IOLine = 1 'IOLine 1, pin 7
> > Pot.Operate = cvTrue 'turn on IOLine 1
> > Wire.Input.Link(Pot.Value)
> > Wire.Output.Link(Srv.Position)
> > End Sub
> >
>
> I know I have made this work before but I'm not on the Windows box
at
> the moment.
>
> We know the oKnob will output 0..255 but oKnobX will output -
128..127.
> We also know that oServoX operates with signed values of -64..63
but
> will accept -128..127.
>
> So, why not try oKnobX and oServoX?
>
> Richard
>

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